3z^3+4y^2+1=

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Solution for 3z^3+4y^2+1= equation:


Simplifying
3z3 + 4y2 + 1 = 0

Reorder the terms:
1 + 4y2 + 3z3 = 0

Solving
1 + 4y2 + 3z3 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4y2 + -1 + 3z3 = 0 + -1

Reorder the terms:
1 + -1 + 4y2 + 3z3 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4y2 + 3z3 = 0 + -1
4y2 + 3z3 = 0 + -1

Combine like terms: 0 + -1 = -1
4y2 + 3z3 = -1

Add '-3z3' to each side of the equation.
4y2 + 3z3 + -3z3 = -1 + -3z3

Combine like terms: 3z3 + -3z3 = 0
4y2 + 0 = -1 + -3z3
4y2 = -1 + -3z3

Divide each side by '4'.
y2 = -0.25 + -0.75z3

Simplifying
y2 = -0.25 + -0.75z3

Reorder the terms:
0.25 + y2 + 0.75z3 = -0.25 + -0.75z3 + 0.25 + 0.75z3

Reorder the terms:
0.25 + y2 + 0.75z3 = -0.25 + 0.25 + -0.75z3 + 0.75z3

Combine like terms: -0.25 + 0.25 = 0.00
0.25 + y2 + 0.75z3 = 0.00 + -0.75z3 + 0.75z3
0.25 + y2 + 0.75z3 = -0.75z3 + 0.75z3

Combine like terms: -0.75z3 + 0.75z3 = 0.00
0.25 + y2 + 0.75z3 = 0.00

The solution to this equation could not be determined.

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